WebWe can tell they are linear because there are 2 variables: X and Y (remember, F (x) is Y) and both variables have exponents = 1. F (X) = X^2 and F (X) = (X-2)^2 are quadratic functions or 2nd degree (exponent on X = 2). When graphed, these create what is called a parabola (looks like a U-shape). WebQuestion Find the total area between the graph of the function f (x) = x +1, graphed below, and the x -axis over the interval [-2, 1] Y 8 7 6 5 4 3 2 1 2 -8 -7 -6 -5 -4 -3 -2 21 0 1 2 3 4 5 6 7 8 -1 -2 -3 -4 -5 -6 -7 -8 Provide your answer below: A= This problem has been solved!
The function f(x) is graphed below. use the graph of the function …
Web22 hours ago · ts) 3. Let g (x) = ∫ − 2 1 f (t) d t and h (x) = ∫ 2 1 f (t) d t where f is the function graphed at the right on the interval [− 5, 5]. a. At what x-coordinate does g have a relative maximum? Does h have a relative minimum? Justify your answer. b. On which subintervals of [− 5, 5] is g concave up? Explain. c. Sketch a graph of g (x ... WebAlgebra Graph f (x)=1 f (x) = 1 f ( x) = 1 Rewrite the function as an equation. y = 1 y = 1 Use the slope-intercept form to find the slope and y-intercept. Tap for more steps... Slope: 0 0 … croft score
Graph y=x+1 Mathway
WebAlgebra Graph f (x)= (x) f (x) = (x) f ( x) = ( x) Rewrite the function as an equation. y = x y = x Remove parentheses. y = x y = x Use the slope-intercept form to find the slope and y-intercept. Tap for more steps... Slope: 1 1 y-intercept: (0,0) ( 0, 0) Any line can be graphed using two points. WebPre-Algebra Graph f (x)= (x-3) (x+1) f (x) = (x − 3)(x + 1) f ( x) = ( x - 3) ( x + 1) Find the properties of the given parabola. Tap for more steps... Direction: Opens Up Vertex: (1,−4) ( 1, - 4) Focus: (1,−15 4) ( 1, - 15 4) Axis of Symmetry: x = 1 x = 1 Directrix: y = −17 4 y = - 17 4 WebGraph f(x)=-1. Step 1. Rewrite the function as an equation. Step 2. Use the slope-intercept form to find the slope and y-intercept. Tap for more steps... Step 2.1. The slope-intercept … buffie\u0027s home decorating